(5/3)x^2+(8/3)x-(4/3)=0

Solution for (5/3)x^2+(8/3)x-(4/3)=0 equation:

(5/3)x^2+(8/3)x-(4/3)=0


Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5/3)x^2+(+8/3)x-(+4/3)=0

We multiply parentheses

8x^2+(+5/3)x^2-(+4/3)=0

We get rid of parentheses

8x^2+(+5/3)x^2-4/3=0

We calculate fractions


8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$